ข้อสอบคณิต O-NET - 2550

$$\begin{gathered} \mathrm{จากโจทย์} \hspace{0.17em}\hspace{0.17em}\hspace{0.17em}x\le 5 \\ -\mathrm{ให้} x = -10 \\ \mathrm{ข้อ} 1. {\left(-10\right)}^2 \le 25 \mathrm{เท็จ} \\ \mathrm{ข้อ} 2. \left|-10\right| \le 5 \mathrm{เท็จ} \end{gathered}$$

$$\begin{gathered} \mathrm{ข้อ} 3. -10·\left|-10\right| = -10·10 \\ = -100 \le 25 \mathrm{จริง} \\ \mathrm{ข้อ} 4. {\left(-10-\left|-10\right|\right)}^2 = {\left(-10-10\right)}^2 \\ = {\left(-20\right)}^2 \\ = 400 \le 25 \mathrm{เท็จ} \end{gathered}$$