ข้อสอบคณิต O-NET - 2559

$$\begin{gathered} \mathrm{จากโจทย์} \mathrm{จะได้} \\ \sqrt[6]{a^{2}b} \sqrt[6]{a^{4}b} = \sqrt[6]{{\left(-5\right)}^2\left(8\right)} \sqrt[6]{{\left(-5\right)}^4\left(8\right)} \\ = \sqrt[6]{5^2{2}^3} \sqrt[6]{5^4{2}^3} \\ = \sqrt[6]{5^2{2}^3{5}^4{2}^3} \\ = \sqrt[6]{5^6{2}^6} \\ = \left(5\right)\left(2\right) = 10 \\ \mathrm{ดังนั้น} \mathrm{ตอบข้อ} 1 \end{gathered}$$